Elementary Electrical Engineering Question Solve April 2011 1b

April 2011 1(b).
Find the potential difference between C and D

I₁=4v/(6Ω+4Ω)                       I₂=8v/(6Ω+10Ω) 

   =0.4A                                         = 0.5A          

 V₁=0.4x6 = 2.4v                     V₂ =0.5x6=3v

I₁ = 4v/(6Ω+4Ω)                       I₂ = 8v/(6Ω+10Ω) 

   = 0.4A                                      = 0.5A 

         

 V₁= 0.4x6 = 2.4v                     V₂ = 0.5x6=3v

From Fig2

V_CA = -V₁   , V_AB = -10v ,     V_BD = V_{2 ,}

V_CD = V_CA+V_AB+V_BD 

         = -2.4v -10v+3v

         = -9.4v      (Ans.)        

Here is the Simulation..............

                               

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